8c^2+26c+8c^2=0

Solution for 8c^2+26c+8c^2=0 equation:

8c^2+26c+8c^2=0

We add all the numbers together, and all the variables

16c^2+26c=0

a = 16; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·16·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*16}=\frac{-52}{32}
=-1+5/8
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*16}=\frac{0}{32}
=0
$